Chapter 4: Integration

The reverse process of differentiation. Think of it as: $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ (n ≠ -1) Find $\int 3x^2 dx$ The definite integral represents total accumulation. Think of it as: $\...

Chapter 4: Integration

AP Exam Weight: 25-35% | Multiple Choice: 10-14 questions | Free Response: Major focus in several questions

📚 Table of Contents

  1. Antiderivatives
  2. Definite Integrals
  3. Integration Techniques
  4. Applications
  5. Fundamental Theorem

1. Antiderivatives ��

Understanding Antiderivatives

The reverse process of differentiation. Think of it as:

  • Finding the original function from its derivative
  • Recovering distance from velocity
  • Working backwards through changes
  • Finding a family of related functions

Basic Rules

Power Rule Integration

xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C (n ≠ -1)

Process

  1. Add 1 to exponent
  2. Divide by new exponent
  3. Add constant of integration
  4. Check by differentiating

Example Walkthrough

Find 3x2dx\int 3x^2 dx

  1. Identify parts:
    • Coefficient: 3
    • Base: x
    • Exponent: 2
  2. Apply rule:
    • Add 1 to exponent: x³
    • Divide by new exponent: x33\frac{x^3}{3}
    • Multiply by coefficient: x3x^3
  3. Add C:
    • Final answer: x3+Cx^3 + C
  4. Verify:
    • Differentiate: ddx(x3+C)=3x2\frac{d}{dx}(x^3 + C) = 3x^2

Common Antiderivatives

Exponential Functions

  • exdx=ex+C\int e^x dx = e^x + C
  • axdx=axlna+C\int a^x dx = \frac{a^x}{\ln a} + C

Trigonometric Functions

  • sinxdx=cosx+C\int \sin x dx = -\cos x + C
  • cosxdx=sinx+C\int \cos x dx = \sin x + C
  • sec2xdx=tanx+C\int \sec^2 x dx = \tan x + C
  • csc2xdx=cotx+C\int \csc^2 x dx = -\cot x + C

Special Cases

  • 1xdx=lnx+C\int \frac{1}{x} dx = \ln|x| + C
  • 11x2dx=arcsinx+C\int \frac{1}{\sqrt{1-x^2}} dx = \arcsin x + C
  • 11+x2dx=arctanx+C\int \frac{1}{1+x^2} dx = \arctan x + C

2. Definite Integrals 🎯

Understanding Definite Integrals

The definite integral represents total accumulation. Think of it as:

  • Area under a curve
  • Total distance traveled
  • Accumulated change
  • Net accumulation over interval

Definition

abf(x)dx=limni=1nf(xi)Δx\int_a^b f(x)dx = \lim_{n \to \infty} \sum_{i=1}^n f(x_i^*)\Delta x

Intuitive Understanding

  • Sum of many tiny rectangles
  • Better approximation as n increases
  • Like slicing area into thin strips
  • Limit of Riemann sums

Process for Riemann Sums

  1. Divide interval into n subintervals
  2. Choose sample points
  3. Form sum of rectangles
  4. Take limit as n → ∞

Example Walkthrough

Approximate 02x2dx\int_0^2 x^2 dx with n = 4

  1. Set up:
    • Δx = (2-0)/4 = 0.5
    • Points: 0, 0.5, 1, 1.5, 2
  2. Calculate heights:
    • f(0) = 0
    • f(0.5) = 0.25
    • f(1) = 1
    • f(1.5) = 2.25
    • f(2) = 4
  3. Form sum:
    • Σf(x)Δx = (0 + 0.25 + 1 + 2.25)·0.5
  4. Compare to actual:
    • Approximation ≈ 2.67
    • Actual = 8/3 ≈ 2.67

Properties

Basic Properties

  1. Reversal of Limits:

    • abf(x)dx=baf(x)dx\int_a^b f(x)dx = -\int_b^a f(x)dx
    • Like walking backwards
    • Changes sign
    • Same magnitude
  2. Additivity:

    • ab[f(x)±g(x)]dx=abf(x)dx±abg(x)dx\int_a^b [f(x) \pm g(x)]dx = \int_a^b f(x)dx \pm \int_a^b g(x)dx
    • Integrals distribute
    • Like adding areas
    • Preserves operations
  3. Constant Multiple:

    • abcf(x)dx=cabf(x)dx\int_a^b cf(x)dx = c\int_a^b f(x)dx
    • Constants come out
    • Scaling property
    • Like area scaling

Advanced Properties

  1. Split Interval:

    • abf(x)dx=acf(x)dx+cbf(x)dx\int_a^b f(x)dx = \int_a^c f(x)dx + \int_c^b f(x)dx
    • Any point c between a and b
    • Additive property
    • Useful for complex problems
  2. Comparison:

    • If f(x) ≥ g(x), then abf(x)dxabg(x)dx\int_a^b f(x)dx ≥ \int_a^b g(x)dx
    • Area comparison
    • Inequality preservation
    • Important for estimation

Common Applications

  1. Area:

    • Between curve and x-axis
    • Between two curves
    • Absolute value for total area
  2. Distance:

    • From velocity
    • Total vs. net
    • Direction matters
  3. Average Value:

    • favg=1baabf(x)dxf_{avg} = \frac{1}{b-a}\int_a^b f(x)dx
    • Mean value theorem
    • Representative value
    • Like center of mass

3. Integration Techniques 🔄

U-Substitution

Understanding the Method

Think of it as:

  • Chain rule in reverse
  • Simplifying complex integrals
  • Pattern recognition
  • Strategic substitution

Process

  1. Identify Parts:

    • Look for composite function
    • Find derivative pattern
    • Choose u carefully
    • Consider du
  2. Set Up:

    • Write u = inner function
    • Find du/dx
    • Solve for dx
    • Rewrite integral
  3. Integrate:

    • Work in terms of u
    • Use basic antiderivatives
    • Keep track of constants
    • Remember +C
  4. Back Substitute:

    • Replace u with original
    • Check answer
    • Verify domain
    • Simplify if needed

Example Walkthrough

Evaluate xcos(x2)dx\int x\cos(x^2)dx

  1. Choose u:
    • Let u = x²
    • du = 2x dx
    • x dx = du/2
  2. Rewrite:
    • cos(u)du2\int \cos(u)\frac{du}{2}
  3. Integrate:
    • 12sin(u)+C\frac{1}{2}\sin(u) + C
  4. Substitute back:
    • 12sin(x2)+C\frac{1}{2}\sin(x^2) + C

Integration by Parts

Formula Understanding

udv=uvvdu\int u dv = uv - \int v du

Think of it as:

  • Product rule backwards
  • Strategic choice of parts
  • Trading complexity
  • Systematic approach

LIATE Order

Choose u from left:

  • Logarithmic
  • Inverse trig
  • Algebraic
  • Trigonometric
  • Exponential

Process

  1. Choose Parts:

    • Select u using LIATE
    • Find dv
    • Calculate v
    • Set up formula
  2. New Integral:

    • Often simpler
    • Sometimes same form
    • May need iteration
    • Watch for patterns

4. Applications 📊

Understanding Applications

Integration solves real-world accumulation problems. Think of it as:

  • Finding total quantities from rates
  • Calculating areas and volumes
  • Determining accumulated change
  • Measuring physical quantities

Area Calculations

Between Curves

A=ab[f(x)g(x)]dxA = \int_a^b [f(x) - g(x)]dx

Process

  1. Find Intersection Points:

    • Solve f(x) = g(x)
    • These are bounds
    • Check crossings
    • Verify domain
  2. Set Up Integral:

    • Top minus bottom
    • Check orientation
    • Consider absolute value
    • Verify bounds
  3. Evaluate:

    • Use appropriate technique
    • Check units
    • Verify reasonableness
    • Consider symmetry

Example Walkthrough

Find area between y = x² and y = x from x = 0 to x = 1

  1. Identify curves:
    • Upper: f(x) = x
    • Lower: g(x) = x²
  2. Set up integral:
    • A=01(xx2)dxA = \int_0^1 (x - x^2)dx
  3. Evaluate:
    • =[x22x33]01= [\frac{x^2}{2} - \frac{x^3}{3}]_0^1
    • =(1213)(00)= (\frac{1}{2} - \frac{1}{3}) - (0 - 0)
    • =16= \frac{1}{6} square units

Volume Calculations

Understanding Methods

  1. Disk Method:

    • V=πab[f(x)]2dxV = \pi\int_a^b [f(x)]^2dx
    • Rotating around x-axis
    • Circular cross sections
    • Like stacking circles
  2. Washer Method:

    • V=πab[R(x)2r(x)2]dxV = \pi\int_a^b [R(x)^2 - r(x)^2]dx
    • Nested cylinders
    • Hollow shapes
    • Difference of disks
  3. Shell Method:

    • V=2πabxf(x)dxV = 2\pi\int_a^b xf(x)dx
    • Cylindrical shells
    • Often easier
    • Alternative approach

Method Selection

  1. Choose Disk/Washer When:

    • Rotating around horizontal line
    • Simple function squared
    • Clear outer/inner functions
    • Straightforward bounds
  2. Choose Shell When:

    • Rotating around vertical line
    • Complex functions
    • Multiple regions
    • Easier integration

Common Mistakes

  1. Setup Errors:

    • Wrong method choice
    • Incorrect radius
    • Wrong axis of rotation
    • Bound confusion
  2. Calculation Errors:

    • Forgetting π
    • Square vs. squared function
    • Wrong substitution
    • Integration mistakes

Other Applications

Work and Pressure

  • W=abF(x)dxW = \int_a^b F(x)dx
  • Force times distance
  • Variable force
  • Accumulation of effort

Average Value

  • favg=1baabf(x)dxf_{avg} = \frac{1}{b-a}\int_a^b f(x)dx
  • Mean value theorem
  • Representative value
  • Typical behavior

5. Fundamental Theorem of Calculus 📐

Understanding FTC

The bridge between derivatives and integrals. Think of it as:

  • Undoing differentiation
  • Connecting rates to totals
  • Simplifying calculations
  • Unifying calculus concepts

Part 1 (FTC1)

Statement

If F'(x) = f(x), then: ddxaxf(t)dt=f(x)\frac{d}{dx}\int_a^x f(t)dt = f(x)

Interpretation

  • Derivative undoes integration
  • Rate of accumulation
  • Instantaneous change
  • Local behavior

Applications

  1. Finding Derivatives:

    • Of integral functions
    • Variable upper limit
    • Chain rule needed
    • Check conditions
  2. Theoretical:

    • Proves relationships
    • Justifies shortcuts
    • Connects concepts
    • Foundation for calculus

Part 2 (FTC2)

Statement

abf(x)dx=F(b)F(a)\int_a^b f(x)dx = F(b) - F(a)

Understanding

  • Evaluate at endpoints
  • Net change
  • Total accumulation
  • Difference of states

Process

  1. Find Antiderivative:

    • Look for patterns
    • Use basic rules
    • Consider techniques
    • Verify derivative
  2. Evaluate:

    • Plug in bounds
    • Subtract results
    • Check signs
    • Verify units

Example Walkthrough

Evaluate 02x3dx\int_0^2 x^3dx

  1. Find F(x):
    • F(x)=x44F(x) = \frac{x^4}{4}
  2. Evaluate bounds:
    • F(2) = 16/4 = 4
    • F(0) = 0
  3. Subtract:
    • 4 - 0 = 4

Common Mistakes

  1. Conceptual:

    • Confusing parts 1 and 2
    • Wrong variable use
    • Missing conditions
    • Integration errors
  2. Computational:

    • Wrong antiderivative
    • Bound substitution
    • Sign errors
    • Constant confusion

Practice Strategies

  1. Understanding:

    • Draw diagrams
    • Use analogies
    • Connect concepts
    • Verify results
  2. Problem Solving:

    • Identify theorem needed
    • Check conditions
    • Show clear work
    • Verify answer

📝 AP-Style Examples

Example 1: FTC Application

Find ddx2xt3dt\frac{d}{dx}\int_2^x t^3dt

Solution:

  1. Use FTC1: Result is x³
  2. No need to integrate
  3. Upper limit becomes variable
  4. Lower limit doesn't affect derivative

Example 2: Area Calculation

Find area between y = x² and y = √x from x = 0 to x = 1

Solution:

  1. Compare functions:
    • √x > x² on (0,1)
  2. Set up integral:
    • 01(xx2)dx\int_0^1 (\sqrt{x} - x^2)dx
  3. Integrate:
    • [2x3/23x33]01[\frac{2x^{3/2}}{3} - \frac{x^3}{3}]_0^1
  4. Evaluate:
    • 2313=13\frac{2}{3} - \frac{1}{3} = \frac{1}{3}

💡 Success Strategies

1. Integration Method Selection

  • Try simplest method first
  • Look for patterns
  • Consider alternatives
  • Check answer reasonableness

2. Common Mistakes

  • Wrong technique choice
  • Missing +C
  • Bound errors
  • Sign mistakes

3. Calculator Tips

  • Check with numerical integration
  • Graph to verify area
  • Use for complex calculations
  • Verify endpoints

🔍 AP Exam Focus

Free Response Tips

  1. Show work:

    • Method selection
    • Step-by-step process
    • Final evaluation
  2. Common Questions:

    • Area/Volume
    • FTC applications
    • Average value
    • Accumulation

Multiple Choice Strategy

  1. Consider:

    • Integration techniques
    • Properties of integrals
    • FTC applications
  2. Check:

    • Units
    • Sign
    • Reasonableness

💡 Pro Tip: Integration is the inverse of differentiation. Always check your answer by differentiating!

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